Advertisements
Advertisements
प्रश्न
A uniform half meter rule balances horizontally on a knife-edge at 29 cm mark when a weight of 20 gf is suspended from one end
1) Draw a diagram of the arrangement
2) What is the weight of the half meter rule?
Advertisements
उत्तर
1) Diagram of the arrangement mentioned in the corresponding question:
2) The center of gravity of a uniform half meter rule is 25 cm
The rule balances horizontally on a knife-edge at 29 cm mark when a weight of 20 kgf is suspended from one end.
The difference in the center of gravity and the point of balance = 29 - 25 = 4 cm (Y).
The weight is suspended at one of the extremes.
let us assume at the 50 cm end
Therefore, the distance from the point of knife edge to the weight
= 50 - 29 = 21 cm (X).
Weight of meter rule = `X/Y` x Suspended weight
∴ Weight of meter rule = `21/4 xx 20` = 105 gf
The weight of the half meter rule is 105 gf.
APPEARS IN
संबंधित प्रश्न
Give an example of a non-contact force which is always of attractive nature
At which point is the centre of gravity situated in a circular lamina?
Where is the centre of gravity of a uniform ring situated?
A square cardboard is suspended by passing a pin through a narrow hole at its one corner. Draw a diagram to show its rest position. In the diagram, mark the point of suspension by the letter S and the centre of gravity by the letter G.
Following Fig shows piece of cardboard of uniform thickness cut into different shapes. Draw two lines to indicate the position of centre of gravity G.
Mention the real-life applications of the center of gravity.
To find the Centre of Gravity of a laminar (2D) object, how many orientations should you suspend it from?
Why is it beneficial for engineers to design tall structures with a low Centre of Gravity?
