Advertisements
Advertisements
प्रश्न
A toroidal solenoid with air core has an average radius of 15 cm, area of cross-section 12 cm2 and has 1200 turns. Calculate the self-inductance of the toroid. Assume the field to be uniform across the cross-section of the toroid.
Advertisements
उत्तर
The self inductance of a toroidal solenoid is given by \[L = \frac{\mu_0 N^2 A}{2\pi r}\]
Here, N = number of turns
A = area of cross-section
r = average radius
\[\therefore L = \frac{4\pi \times {10}^{- 7} \times \left( 1200 \right)^2 \times 12 \times {10}^{- 4}}{2\pi \times 15 \times {10}^{- 2}}\]
\[ = 230 . 4 \times {10}^{- 5} H\]
APPEARS IN
संबंधित प्रश्न
The currents flowing in the two coils of self-inductance L1 = 16 mH and L2 = 12 mH are increasing at the same rate. If the power supplied to the two coil is equal, find the ratio of the energies stored in the two coils at a given instant ?
A magnetic flux of 8 × 10−4 weber is linked with each turn of a 200-turn coil when there is an electric current of 4 A in it. Calculate the self-inductance of the coil.
Obtain an expression for the self-inductance of a solenoid.
Two coils of self inductances 2 mH and 8 mH are placed so close together that the effective flux in one coil is completely linked with the other. The mutual inductance between these coils is ______.
An inductor may store energy in
In a fluorescent lamp choke (a small transformer) 100 V of reverse voltage is produced when the choke current changes uniformly from 0.25 A to 0 in a duration of 0.025 ms. The self-inductance of the choke (in mH) is estimated to be ______.
What is meant by magnetic coupling coefficient?
The current in a coil changes from 50A to 10A in 0.1 second. The self inductance of the coil is 20H. The induced e.m.f. in the coil is ______.
In a coil, the current changes form −2 A to +2 A in 0.2 s and induces an emf of 0.1 V. The selfinductance of the coil is ______.
