Advertisements
Advertisements
प्रश्न
A sum of Rs. 65000 is invested for 3 years at 8 % p.a. compound interest.
Find the compound interest earned in the first two years.
Advertisements
उत्तर
`"C"_1 + "C"_2 = 5200 + 5616 = 10816`
संबंधित प्रश्न
At what rate % p.a. will a sum of Rs. 4000 yield Rs. 1324 as compound interest in 3 years?
Mr Kumar borrowed Rs. 15000 for two years. The rates of interest for two successive years are 8% and 10% respectively. If he repays Rs. 6200 at the end of the first year, find the outstanding amount at the end of the second year.
Calculate the amount and the compound interest for the following:
Rs.25, 000 at `8 2/5 %` p.a. in `1 1/3` years
Alisha invested Rs 75000 for 4 years at 8 % p.a. compound interest ,
Find the amount at the end of the second year.
Rajan borrowed Rs 90,000 at 15% p.a. compound interest. If he repays Rs 35,000 at the end of each year, find the amount of loan outstanding at the beginning of the fourth year.
Archana borrowed Rs 18,000 from Ritu at 12% p.a. compound interest. If at the end of the 1st, 2nd, and 3rd years, Archana returned Rs 5,250, Rs 5,875 and Rs 6,875 respectively, find the amount Archana has to pay Ritu at the end of the 4th year to clear her debt.
Prakash borrowed Rs 10,000 from Rajesh for 2 years at 6% and 8% p.a. compound interest for successive years. If Prakash returns Rs 5,600 at the end of the first year, how much does he have to give to Rajesh at the end of the second year to clear the loan?
A man's savings increases by Rs 50 every year. If he saves Rs 500 in the first year and puts it at 10% compound interest, find his savings at the end of the third year.
How much will Rs. 50,000 amount to in 3 years, compounded yearly, if the rates for the successive years are 6%, 8% and 10% respectively?
A man lends Rs. 12,500 at 12% for the first year, at 15% for the second year and at 18% for the third year. If the rates of interest are compounded yearly ; find the difference between the C.I. fo the first year and the compound interest for the third year.
