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प्रश्न
A solid metallic cube having a total surface area of 24 m2 is uniformly heated. If its temperature is increased by 10°C, calculate the increase in the volume of the cube.
(Given: α = 5.0 × 10−4°C−1)
विकल्प
2.4 × 106 cm3
1.2 × 105 cm3
6.0 × 104 cm3
4.8 × 105 cm3
MCQ
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उत्तर
1.2 × 105 cm3
Explanation:
Given: α = 5.0 × 10−4°C−1
ΔT = 10
Total surface area of the cube = 24 m2
⇒ 6a2 = 24
⇒ a2 = `24/6`
⇒ a2 = 4 ...[Taking square root on both sides]
⇒ a = 2 m
Initial volume (V) = a3
= 23
= 8 m
Volume expansion (ΔV) = 3αVΔT
= 3 × (5 × 10−4) × 8 × 10
= 0.12 m3
= 0.12 × 106 cm3
= 1.2 × 105 cm3
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