Question

A solid metal sphere of volume 0.31 m³ is dropped in an ocean where water pressure is 2 × 10⁷ N/m². Calculate change in volume of the sphere if the bulk modulus of the metal is 6.1 × 10¹⁰ N/m².

Answer 1

Given: V = 0.31 m³

dP = 2 × 10⁷ N/m²

K = 6.1 × 10¹⁰ N/m²

To find: Change in volume (dV) = ?

Formula: K = `V xx (dP)/(dV)`

dV = `(V xx (dP))/K`

dV = `(0.31 xx 2 xx 10^7)/(6.1 xx 10^10)`

dV = 10⁻⁴ m³

∴ The change in volume of the sphere is 10⁻⁴ m³.