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प्रश्न
A sector of 56°, cut out from a circle, contains 17.6 cm2. Find the radius of the circle.
योग
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उत्तर
Area of the sector = 17.6 cm2
Area of the sector`=(pi"r"^2theta)/360`
`=> 17.6 =22/7xx"r"^2xx56/360`
`=> "r"^2 = (17.6 xx7xx360)/(22xx56)`
⇒ r = 6m
∴ Radius of the circle = 6 cm
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