Question

A sample of ammonium nitrate when heated yields 8.96 litres of steam (measured at STP)
NH₄NO₃ → N₂O + 2H₂O
What mass of ammonium nitrate should be heated to produce 8.96L of steam?

Answer 1

Molecular mass of NH₄NO₃ = 80
44.8L of steam is liberated by = 80g of NH₄NO₃
8.96L of steam will be liberated by = 80 x 8.96 / 44.8 = 16L