Question

A room is 5m long, 2m broad and 4m high. Calculate the number of persons it can accommodate if each person needs 0.16m³ of air.

Answer 1

Given that:
Length (l) of the room = 5m
Breadth (b) of the room = 2m
Height (h) of the room = 4m
∴ Volume of the air in the room
= l x b x h
= 5 x 2 x 4
= 40m³
Since, 1 person needs = 0.16m³ of air
i.e., 0.16m³ of air = 1 person

∴ 1m³ of air = `(1)/(0.16)"person"`

So, 40m³ of air = `(1)/(0.16) xx 40`

= `(40)/(0.16) xx (100)/(100)`

= `(4000)/(16)`
= 250 Persons
Thus, the room can accommodate 250 persons.