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प्रश्न
A railway track goes around a curve having a radius of curvature of 1 km. The distance between the rails is 1 m. Find the elevation of the outer rail above the inner rail so that there is no side pressure against the rails when a train goes around the curve at 36 km/hr.
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उत्तर
Given:
Radius of curve, r = 1 km = 1000 m,
Speed of train, v = 36 km/hr = `36 xx 5/18` = 10 m/s
To find: Elevation of rails (h)
Formulae:
- tan θ = `"v"^2/"rg"`
- h = l sinθ
Calculation:
From formula (i),
θ = `tan^-1("v"^2/"rg")`
= `tan^-1(100/(1000 xx 9.8))`
= `tan^-1(1/98)`
= `tan^-1(10^-1/98)`
= `tan^-1(0.1020 xx 10^-1)`
= `tan^-1(0.01020)`
∴ θ = 0°35'
From formula (ii),
h = l sin θ
h = 1 × sin (0°35′)
= 0.0102 m
∴ h = 1.02 cm

The elevation of the outer rail above the inner rail is 1.02 cm.
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