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प्रश्न
A proton describes a circle of radius 1 cm in a magnetic field of strength 0.10 T. What would be the radius of the circle described by an α-particle moving with the same speed in the same magnetic field?
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उत्तर
Given:
Radius of the circle, r = 1 cm
Magnetic field = 0.10 T
We know that the charge of a proton is e and that of an alpha particle is 2e. Also, the mass of a proton is m and that of an aplha particle is 4m.
Suppose, both the particles are moving with speed v.
According to the question,
`r_p =(mv)/(eB),` where rp is the radius of the circle descrinbed by the proton.
0.01 = `(mv)/(exx00.1)`
`r_a = (4mv)/(2eB)`
`r_a = (4mv)/(2eB)`............(ii)
On dividing equation (ii) by (i), we get:
`(ra)/0.01 = ((4mvxxexx0.1)/(2exx0.1xxmv))`
`r_a = 0.02 m =2 cm`
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