Question

A pole casts a shadow of length \[2\sqrt{3}\]  m on the ground, when the sun's elevation is 60°. Find the height of the pole.

 

Answer 1

Let AB be the height of the pole and BC be the shadow of the pole.

Given:
BC =\[2\sqrt{3}\]

\[\angle\]ACB = 60°

In ∆ABC,

\[\tan60^o = \frac{AB}{BC}\]
\[ \Rightarrow \sqrt{3} = \frac{AB}{2\sqrt{3}}\]
\[ \Rightarrow AB = 6 m\]

Hence, the height of the pole is 6 m.