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A point object in the air is placed symmetrically at a distance of 60 cm in front of a concave spherical surface with a refractive index of 1.5. If the radius of curvature of the surface is 20 cm

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प्रश्न

A point object in the air is placed symmetrically at a distance of 60 cm in front of a concave spherical surface with a refractive index of 1.5. If the radius of curvature of the surface is 20 cm, find the position of the image formed.

संख्यात्मक
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उत्तर

We can use the mirror formula to find the position of the image formed by the concave spherical surface:

Since the object is placed symmetrically in front of the surface, we have:

u = 60 cm

Now, we can substitute these values into the formula:

`n_2/v - n_1/u = (n_2 - n_1)/R`

⇒ `1.5/v = (1.5 - 1)/(-20) + 1/(-60)`

⇒ `1.5/v = 0.5/(-20) - 1/60`

⇒ `1.5/v = -1/40 - 1/60`

⇒ `1.5/v = (-6 - 4)/240`

⇒ `1.5/v = (-10)/240`

⇒ `v = 240 xx 1.5/(-10) = -36`

Taking the reciprocal of both sides, we get:

`v = -36` cm

The negative sign indicates that the image is formed on the same side of the surface as the object, which means it is a virtual image. So, the image is formed 36 cm behind the concave spherical surface.

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