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प्रश्न
A person travelling on a straight line moves with a uniform velocity v1 for some time and with uniform velocity v2 for the next equal time. The average velocity v is given by
विकल्प
- \[v = \frac{v_1 + v_2}{2}\]
- \[v = \sqrt{v_1 v_2}\]
- \[\frac{2}{v} = \frac{1}{v_1} + \frac{1}{v_2}\]
- \[\frac{1}{v} = \frac{1}{v_1} + \frac{1}{v_2}\]
MCQ
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उत्तर
\[v = \frac{v_1 + v_2}{2}\]
Velocity is uniform in both cases; that is, acceleration is zero.
We have: \[d_1 = v_1 t\] and \[d_2 = v_2 t\]
We have: \[d_1 = v_1 t\] and \[d_2 = v_2 t\]
Total displacement, \[d = d_1 + d_2\]
Total time, \[t = t + t = 2t\]
Total time, \[t = t + t = 2t\]
∴ Average velocity,
\[v = \frac{d_1 + d_2}{2t} = \frac{v_1 + v_2}{2}\].
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