Question

A pendulum is performing simple harmonic motion. The acceleration of the bob is 20 cm s⁻² at a distance of 5 cm from mean position. The time period of oscillation is ______.

विकल्प

• 2 s

• π s

• 2π s

• 1 s

Answer 1

A pendulum is performing simple harmonic motion. The acceleration of the bob is 20 cm s⁻² at a distance of 5 cm from mean position. The time period of oscillation is π s.

Explanation:

Given: Acceleration (a) = 20 cm/s²

x = 5 cm

Acceleration (a) = ω²x

ω = `sqrt (a/x)`

= `sqrt (20/5)`

= `sqrt 4`

= 2 rad/s

Period (T) = `(2 pi)/omega`

= `(2 pi)/2`

= π s