Question

A pair of dice is thrown. Find the probability of getting a sum of 10 or more, if 5 appears on the first dice.

Answer 1

In throwing a dice, total possible outcome = {1, 2, 3, 4, 5, 6} 

n(S) = 6 

For two dice, n(S) = 6 × 6 = 36 

Favorable cases where the sum is 10 or more with 5 on 1^st die = {(5, 5), (5, 6)} 

Event of getting the sum is 10 or more with 5 on 1^st die = n(E) = 2 

Probability of getting a sum of 10 or more with 5 on 1^st die = `(n(E))/(n(S))`

= `2/36`

= `1/18`