Question

A pair of dice is thrown 3 times. If getting a doublet is considered a success, find the probability of two successes.

Answer 1

Let X denote the number of times of getting doublet.

If a pair of dice is thrown, then there are total 36 possible outcomes, out of which 6 [i.e. (1, 1), (2, 2), …,(6, 6)] are doublets.

∴ P(getting a doublet) = p = `(6)/(36) = (1)/(6)`

∴ q = 1 – p

= `1 - (1)/(6)`

= `(5)/(6)`

Given, n = 3

∴ X ∼ B `(3, 1/6)`

The p.m.f. of X is given by

P(X = x) = `""^3"C"_x (1/6)^x (5/6)^(3 - x)`, x = 0, 1, 2, 3

∴ P(two successes) = P(X = 2)

= `""^3"C"_2(1/6)^2(5/6)`

= `3 xx (1)/(36) xx (5)/(6)`

= `(5)/(72)`

= 0.069