Question

A pair of adjacent coils has a mutual inductance of 1.5 H. If the current in one coil changes from 0 to 20 A in 0.5 s, what is the change of flux linkage with the other coil?

Answer 1

`e=-M(dI)/dt`

`e=-1.5xx(20-0)/0.5`

=−60 V

So, the flux linked with the other coil is given by

∆ϕ=e×∆t=−60×0.5=−30 Wb