Advertisements
Advertisements
प्रश्न
A nut is opened by a wrench of length 25 cm. If the least force required is 10 N, find the moment of force needed to turn the nut.
Advertisements
उत्तर
Distance = 25 cm = `25/100` = 0.25 m
Force = 10 N
Moment of force = ?
Moment of force = Force × Distance
= 10 × 0.25
= 2.5 N m
APPEARS IN
संबंधित प्रश्न
A force is applied on (i) a non-rigid body and (ii) a rigid body. How does the effect of the force differ in the above two cases?
What do you mean by the clockwise and anti-clockwise moment of force?
Sleepers are used below the rails.
The moment of a force of 25 N about a point is 2.5 N m. Find the perpendicular distance of force from that point.
Give two examples of a couple's actions in our daily life.
The figure shows two forces each of magnitude 10 N acting at the point A and B at a separation of 50 cm, in opposite directions. Calculate the resultant moment of two forces about the point.
- A,
- B and
- O situated exactly at the middle of the two forces.

One joule is the amount of work done when a force of ......... moves a body through a distance of .......
The diagram shows a uniform metre rule weighing 100gf, pivoted at its centre O. Two weights 150gf and 250gf hang from the point A and B respectively of the metre rule such that OA = 40 cm and OB = 20 cm. Calculate :
the difference of anticlockwise and clockwise moment

State one factor on which the magnitude of a non-contact force depends. How does the magnitude of a non-contact force change along with distance?
What is meant by the term ‘moment of force’? If the moment of force is assigned a negative sign then will the turning tendency of the force be clockwise or anti-clockwise?
