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प्रश्न
A nut can be opened by a lever of length 0.25 cm by applying a force of 80 N. What should be the length of lever, if a force of 32 N is enough to open the nut?
संख्यात्मक
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उत्तर
The work done to open the nut in both cases is same.
∴ Work done by the lever in case (ii) = work done by lever in case (i)
Effort × Effort arm in case (ii) = effort × effort arm in case (i)
32 N × Effort arm in case (ii) = 80 N × 0.25 cm
Effort arm in case (ii) \[= \frac{80 \times 0.25}{32} \]
\[= \frac{20}{32} \]
= 0.625 cm
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