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A needle of a sewing machine moves along a path of amplitude 4 cm with a frequency of 5 Hz. Find its acceleration (130) s after it has crossed the mean position. - Physics

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प्रश्न

A needle of a sewing machine moves along a path of amplitude 4 cm with a frequency of 5 Hz. Find its acceleration `(1/30)` s after it has crossed the mean position.

योग
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उत्तर

Data: A = 4 cm, n = 5 Hz, t = `(1/30)` s, a = - ω2 x, |a| = ω2

as x = A sin ω t

∴ |a| = ω2 A sin ω t

`= (2  π " n")^2 "A" sin (2  π " n") xx 1/30` 

`= 4 pi^2 "n"^2 " A" sin (2  pi  5) 1/30`

`= 4pi^2 xx 25 xx 4 sin  (10 pi)/30`

`= 100 pi^2 xx 4 sin  pi/3`

`= 100pi^2 xx cancel(4)^2 xx sqrt3/cancel(2)_1`

`= 100 pi^2 xx 2 xx 1.732`

`= 100 xx pi^2 xx 3.464`

`= 346.4 xx 9.87`

= 3420 cm/s2

= 3420 × 10-2 m/s2

|a| = 34.2 m/s2

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Amplitude (A), Period (T) and Frequency (N) of S.H.M.
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अध्याय 5: Oscillations - Exercises [पृष्ठ १३०]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
अध्याय 5 Oscillations
Exercises | Q 10 | पृष्ठ १३०

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