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A Moving-coil Galvanometer Has a 50-turn Coil of Size 2 Cm × 2 Cm. It is Suspended Between the Magnetic Poles Producing a Magnetic Field of 0.5 T. - Physics

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प्रश्न

A moving-coil galvanometer has a 50-turn coil of size 2 cm × 2 cm. It is suspended between the magnetic poles producing a magnetic field of 0.5 T. Find the torque on the coil due to the magnetic field when a current of 20 mA passes through it.

योग
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उत्तर

Given : 

Number of turns in the coil, n = 50
Area of the cross section of the coil, A = 2 cm × 2 cm = 2 × 2 × 10−4 m2

Current flowing through the coil, `I = 20 × 10^−3 A`

Magnetic field strength due to the presence of the poles, B = 0.5 T

The torque experienced by the coil placed in an external magnetic field `(tau)` is given by 

`τ = nI (vec A xx vec B)`

⇒ `τ = nIAB  sin 90^circ`

⇒ `τ = 50 xx 20 xx 10^-3 xx 4 xx 10^-4 xx 0.5`

⇒ `τ = 2 xx 10^-4  "N - m"`

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अध्याय 14: Permanent Magnets - Exercises [पृष्ठ २७८]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 14 Permanent Magnets
Exercises | Q 17 | पृष्ठ २७८

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