Question

A monkey is climbing a rope of length 15 m in a circus. The rope is tied to a vertical pole from its top. Find the height of the pole, if the angle, the rope makes with the ground level is equal to 60°.

Answer 1

The pole AB in the illustration is where the rope is attached from point C on the ground.

So, AC = 15 m, ∠ACB = 60°

Now, in ΔABC,

`(AB)/(AC)` = sin 60°

`(AB)/15 = sqrt(3)/2`

AB = `(15sqrt(3))/2`

AB = 12.99 m

As a result, the pole's height is 12.99 m.