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प्रश्न
A metre scale is pivoted from the 0 cm mark and is free to rotate in the vertical plane. A 50 g weight is suspended from the 20 cm mark as shown in the figure. Calculate the moment of force in gf × cm and in N m.
संख्यात्मक
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उत्तर
Given Data:
Force (F) = 50 gf
Pivot position = 0 cm mark
Position of weight = 20 cm mark
Perpendicular distance (d) = 20 − 0 = 20 cm
1. Calculation in gf . cm:
Moment of Force = Force (F) × Distance (d)
= 50 gf × 20 cm
= 1000 gf . cm
2. Calculation in N . m:
Convert Force to Newtons = 50 gf = `50/1000` kgf = 0.05 kgf = 0.05 × 9.8 N = 0.49 N
Convert Distance to Meters = 20 cm = `20/100` m = 0.2 m
Moment of Force = 0.49 N × 0.2 m
= 0.098 N . m
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