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A Man Fixes the Selling Price of His Goods at 50% Above the Cost Price. He Sells One-third of His Stock at this Price, One-third of His Stock at a Discount of 20% on the Original Selling Price - Mathematics

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प्रश्न

A man fixes the selling price of his goods at 50% above the cost price. He sells one-third of his stock at this price, one-third of his stock at a discount of 20% on the original selling price, and the rest at a discount of 40% on the original selling price. Find the gain percent altogether.

योग
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उत्तर

Let the C.P. of each article bought = Rs.100
Let the number of articles bought = x
∴ C.P. of the articles = Rs.100x
M.P. of the articles
= Rs.100 + 50% of Rs.100
= Rs.150
Stage 1 :
No. of articles sold at Rs.150 = `x/(3)`

∴ S.P. of `x/(3)`articles

= Rs.`(150 xx x/3)`
= Rs.50x
Stage 2 :
Discount
= 20% of Rs.150
= `(20)/(100) xx "Rs."150`
= Rs.30
∴ S.P. 
= Rs.150 - Rs.30
= Rs.120
No. of articles sold at Rs.120 = `x/(3)`

∴ S.P. of `x/(3)`articles

= Rs.`(120 xx x/3)`
= Rs.40x
Stage 3 :
Discount
= 40% of Rs.150
= `(40)/(100) xx "Rs."150`
= Rs.60
∴ S.P.
= Rs.150 - Rs.60
= Rs.90
No. of articles sold at Rs.90 = `x/(3)`

∴ S.P. of `x/(3)`articles

= Rs.`(90 xx x/3)`
= Rs.30x
Total S.P. of all articles
= Rs.50x + Rs.40x + Rs.30x
= Rs.120x
∵ S.P. > C.P., therefore there is a gain
Gain
= Rs.120x - Rs.100x
= Rs.20x
Gain %
= `"gain"/"C.P." xx 100`

= `(20x)/(100x) xx 100`
= 20%.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Profit , Loss and Discount - Exercise 2.4

APPEARS IN

फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 2 Profit , Loss and Discount
Exercise 2.4 | Q 21

संबंधित प्रश्न

After offering discount of 10% on marked price, a customer gets total discount of 17 rupees. To find the cost price for the customer, fill in the following boxes with appropriate numbers and complete the activity.

Suppose, marked price of the item = 100 rupees

Therefore, for customer that item costs `square` - `square`  = 90 rupees

Hence, when the discount is `square` then the selling price is `square` rupees. 

Suppose when the discount is `square` rupees, the selling price is x rupees.

∴ `x/square=square/square`

∴ x = `(squarexxsquare)/square`

∴ x = `square`

∴ the customer will get the item for 153 rupees.


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