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A Man Borrows Rs.20000 at 10% per Annum Compound Interest Payable Annually. If He Repays Rs.5000 at the End of the First Year and Rs.10000 at the End of the Second Year - Mathematics

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प्रश्न

A man borrows Rs.20000 at 10% per annum compound interest payable annually. If he repays Rs.5000 at the end of the first year and Rs.10000 at the end of the second year; how much should he pay at the end of the third year in order to clear the account? Find the answer correct to the nearest rupee.

योग
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उत्तर

For 1st half year : P = Rs.2000, R = 10% and T = 1 year

Interest = Rs.`(20000 xx 10 xx 1)/(100)`
 =Rs.2000
Amount
= Rs.20000 + Rs.2000
= Rs.22000
Money paid at the end of 1st half year = Rs.5000
Balance money for 2nd half year
 =Rs.22000 - Rs.5000
= Rs.17000
For 2nd half year : P = Rs.17000; R = 10% and T = 1 year

Interest = Rs.`(17000 xx 10 xx 1)/(100)`
 = Rs.1700
Amount
 = Rs.17000 + Rs.1700
 = Rs.18700
Money paid at the end of 2nd half year = Rs.10000
Balance money for 3rd half year 
= Rs.18700 - Rs.10000
 =Rs.8700
For 3rd half year : P = Rs.8700; R = 10% and T = 1 year

Interest = Rs.`(8700 xx 10 xx 1)/(100)`
 = Rs.870
Amount
 = Rs.8700 + Rs.870
 =Rs.9570
A man should pay Rs.9570 at the end of 3rd year to clear the account.

shaalaa.com
Concept of Compound Interest - Use of Compound Interest in Computing Amount Over a Period of 2 Or 3-years
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Compound Interest - Exercise 3.1

APPEARS IN

फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 3 Compound Interest
Exercise 3.1 | Q 22

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