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A Man Borrows Rs.10,000 at 10% Compound Interest Compounded Yearly. at the End of Each Year, He Pays Back 20% of the Amount for that Year. How Much Money is Left Unpaid Just After the Second Year? - Mathematics

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प्रश्न

A man borrows Rs.10,000 at 10% compound interest compounded yearly. At the end of each year, he pays back 20% of the amount for that year. How much money is left unpaid just after the second year ?

योग
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उत्तर

For 1st year :

P = Rs. 10,000; R = 10% and T = 1 year

Interest = Rs. `[10,000 xx 10 xx 1]/100` = Rs. 1,000

Amount at the end of 1st year = Rs. 10,000 + Rs. 1,000 = Rs. 11,000

Money paid at the end of 1st year = 20% of Rs. 11,000 = Rs. 2,200

∴ Principal for 2nd year = Rs. 11,000 - Rs. 2,200 = Rs. 8,800

For 2nd year :

P = Rs. 8,800; R = 10% and T= 1 year

Interest = Rs. `[8,800 xx 10 xx 1]/[100]`= Rs. 880

Amount at the end of 2nd year = Rs. 8,800 + Rs. 880 = Rs. 9,680

Money paid at the end of 2nd year = 20% of Rs. 9,680 = Rs.1,936

∴ Principal for 3rd year =Rs. 9,680 - Rs. 1,936 = Rs. 7,744.

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अध्याय 2: Compound Interest (Without using formula) - Exercise 2 (C) [पृष्ठ ३८]

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सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 2 Compound Interest (Without using formula)
Exercise 2 (C) | Q 12 | पृष्ठ ३८

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