Advertisements
Advertisements
प्रश्न
A lens forms an erect, magnified, and virtual image of an object. Where is the object placed in relation to the lens?
Advertisements
उत्तर
The object is placed between the lens and focus (F1).
APPEARS IN
संबंधित प्रश्न
The speed of light in air is 3 × 108 m s-1. Calculate the speed of light in glass. The refractive index of glass is 1.5
Draw a neat labelled ray diagram to show the formation of an image by a magnifying glass. State three characteristics of the image.
The focal length of a convex lens is 25 cm. At what distance from the optical centre of the lens an object be placed to obtain a virtual image of twice the size?
The magnification by a lens is +0.5. Name the lens and state how are u and v related?
What are conjugate foci?
Why is the focal length of the lens, used as a magnifying glass, kept short?
Name the lens for which magnification can be 1. For what position of the object will the magnification be 1?
Show with the help of a ray diagram, the path of the ray when incident normally on the first surface of the glass block, through the block and the liquid.
What is a magnifying glass (or a simple microscope)? Draw a ray diagram to show how a convex lens may be used as a magnifying glass. Where should the object be placed? State three characteristics of the image formed.
(i) Draw a ray diagram to show how the lens can be used as a ‘magnifying glass’? State the nature of the lens.
(ii) In what respect does the image in (i) above different from the image formed by a concave lens?
