Advertisements
Advertisements
प्रश्न
A lawn is in the shape of a semicircle of diameter 42m. the lawn is surrounded by a flower bed of width 7m all round. Find the area of the flower bed in m2.
Advertisements
उत्तर

There are two concentric semi circles. The diameter of the inner circle = 42 or radius, a = 21m. The radius of the outer circle, b = 21 + 7 = 28m.
Because the radius of a Circle with diameter d is r = `"d"/(2)`
The Area of the inner Semi-circle with radius a = `(pi"a"^2)/(2) = (pi21^2)/(2)`
∴ The Area of the outer Semi-circle with radius b = `(pi"b"^2)/(2) = (pi28^2)/(2)`
and The Area of a Semi-circle with radius r = `(pi"r"^2)/(2)`
The Area of the flower bed
= `(pi28^2)/(2) - (pi21^2)/(2)`
= `pi/(2)(28^2 - 21^2)`
= `pi/(2)(784 - 441)`
= `pi/(2)(343)`
= `(22)/(7 xx 2)(343)`
= 539m2.
APPEARS IN
संबंधित प्रश्न
A rectangular park 358 m long and 18 m wide is to be covered with grass, leaving 2.5 m uncovered all around it. Find the area to be laid with grass.
A path of width 3.5 m runs around a semi-circular grassy plot whose perimeter is 72 m . Find the area of the path .
`("Use" pi= 22/7) `
In the following figure find the area of the shaded region. (Use π = 3.14)

In the following figure, shows the cross-section of railway tunnel. The radius OA of the circular part is 2 m. If ∠AOB = 90°, calculate:
the height of the tunnel

If the area of a square is same as the area of a circle, then the ratio of their perimeters, in terms of π, is
A pendulum swings through an angle of 30° and describes an arc 8.8 cm in length. Find the length of the pendulum.
The area of the sector of angle θ° of a circle with radius R is
A racetrack is in the form of a ring whose inner circumference is 352 m and outer circumference is 396 m. Find the width and the area of the track.
The radii of two circles are in the ratio 3: 8. If the difference between their areas is 2695π cm2, find the area of the smaller circle.
The area of the circle is 154 cm2. The radius of the circle is ______.
