Question

A ladder 15 m long makes an angle of 60° with the wall. Find the height of the point where the ladder touches the wall.

Answer 1

AC = 15 m is the ladder. Let AB = h be the height. 

\[In \bigtriangleup ABC, \]
\[\sin60^o = \frac{AB}{AC} = \frac{h}{15}\]
\[ \Rightarrow \frac{\sqrt{3}}{2} = \frac{h}{15}\]
\[ \Rightarrow h = \frac{15\sqrt{3}}{2}\]