Question

A group consists of 12 persons, of which 3 are extremely patient, other 6 are extremely honest and rest are extremely kind. A person from the group is selected at random. Assuming that each person is equally likely to be selected, find the probability of selecting a person who is 

1. extremely patient,
2. extremely kind or honest.
   
   Which of the above values you prefer more?

Answer 1

Total number of persons = 12.

Number of persons who are extremely patient = 3.

Number of persons who are extremely honest = 6.

Number of persons who are extremely kind = 12 − 3 − 6 = 3.

i. P(selecting a person who is extremely patient) = `("Number of favourable outcomes")/"Number of all possible outcomes"`

`= 3/12 = 1/4`

Thus, the probability of selecting a person who is extremely patient is `1/4`.

ii. P(selecting a person who is extremely kind or honest) =`("Number of favourable outcomes")/"Number of all possible outcomes"`

`= 6+3/12 = 9/12= 3/4 `

Thus, the probability of selecting a person who is extremely kind or honest is `3/4`.

From the three given values, we prefer honesty more.