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प्रश्न
A function f is defined by f(x) = 2x – 3 find `("f"(0) + "f"(1))/2`
योग
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उत्तर
f(x) = 2x – 3
f(0) = 2(0) – 3 = – 3
f(1) = 2(1) – 3 = 2 – 3 = – 1
`("f"(0) + "f"(1))/2= (-3 - 1)/2 = (-4)/2`
`("f"(0) + "f"(1))/2` = – 2
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