Advertisements
Advertisements
प्रश्न
A force of 50 kgf is applied to the smaller piston of a hydraulic machine. Neglecting friction, find the force exerted on the large piston, if the diameters of the pistons are 5 cm and 25 cm respectively.
Advertisements
उत्तर
Ratio of diameter of smaller piston to bigger piston = 5 : 25
∴ Ratio of area of smaller piston to bigger piston = 25 : 625
Force applied on smaller piston , F1 = 50 kgf
Let F2 be the force on the bigger piston .
By the principle of hydraulic machine ,
Pressure on narrow piston = pressure on wider piston
or , `F_1/A_1 = F_2/A_2`
or , `F_1/F_2 = A_1/A_2`
or , `50/F_2 = 25/625`
or , `F_2 = 50 xx 625/25 = 1250` kgf
संबंधित प्रश्न
If the mechanical advantage of the handle of the pump plunger is 8, calculate the force applied at the end of the handle of the pump plunger.
State the principle on which Brahma press depends.
For what purpose is the acid battery hydrometer used?
Assertion: Pascal’s law is the working principle of a hydraulic lift.
Reason: Pressure is thrust per unit area.
Match the following:
| 1. | Hydraulic press | a. | Archimedes |
| 2. | Cartesian Diver | b. | Floatation |
| 3. | Hydrostatic Balance | c. | Pascal’s law |
| 4. | Hydrometer | d. | Buoyancy |
An iceberg of density 700 kg/m3 is floating in the water of density 1000 kg/m3. The percentage of the volume of ice cube outside the water is:
A hydraulic press can lift 100 kg when a mass 'm' is placed on the smaller piston. It can lift ______ kg when the diameter of the larger piston is increased by 4 times and that of the smaller piston is decreased by 4 times keeping the same mass 'm' on the smaller piston.
