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A First Order Reaction Takes 30 Minutes for 50% Completion. Calculate the Time Required for 90% Completion of this Reaction. - Chemistry

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प्रश्न

A first order reaction takes 30 minutes for 50% completion. Calculate the time required for 90% completion of this reaction.

(log 2 = 0.3010)

संख्यात्मक
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उत्तर

For the given firstorder reaction, the rate constant for 50% completion is given by

`k=2.303/t`

Here,

t=Time taken for 50% completion=30 min

[R]o=Initial concentration of the reactant

[R]=Final concentration of the reactant

Let [R]0 be 100 and due to 50% completion of reaction, [R] will be 10050, i.e. 50.

Putting values in (i), we get

`k=2.303/30`

  `=2.303/30`

For the same reaction, the time required for 90% completion of the reaction can be computed using the expression

`k=2.303/t`

Here,

[R]=Final concentration of reactant=10090=10

(ii) Rate = `(Δ x)/(Δ t)`

= `2.303/k log10 = 2.303/k`

By putting the value of k here,we get

t = `(2.303 xx 1800)/(2.303 xx 0.3010)`

= `5.98 xx 10^3 "sec"`

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2014-2015 (March) Delhi Set 1

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