Question

A farmer borrows Rs.1,000 and agrees to repay with a total interest of Rs. 140 in 12 installments, each installment being less that the preceding installment by Rs. 10. What should be his first installment?

Answer 1

As each installment being less that the preceding installment by Rs. 10 the
installments are in A.P.
S₁₂ = 1000 + 140 = 1140

n = 12, d = −10

`s_n=n/2[2a+(n-1)d]`

`s_12=12/2[2a+(11)(-10)]`

`1140=6[2a-110]`

`1140/6=[2a-110]`

190 = [2a − 110]

2a = 190 + 110

2a = 300

a = `300/2`

a = 150

The first installment = Rs. 150.