Question

A die is tossed once. Find the probability of getting an even number or a multiple of 3 ?

Answer 1

The number of possible outcomes is six: 1, 2, 3, 4, 5 and 6.

Among these numbers; 2, 4, 6 are the even numbers and 3, 6 are the multiples of 3.

Favourable outcomes are {2, 3, 4, 6}.

So, P (getting an even number or a multiple of 3) `=\text{Number of favouravle outcomes}/\text{Total number of all possible outcomes}=4/6=2/3`