Question

A cylindrical container with internal radius of its base 10 cm, contains water up to a height of 7 cm. Find the area of the wet surface of the cylinder.

Answer 1

Internal radius of the cylinderical container = 10 cm 

Height of water = 7 cm 

Therefore, surface area of the wet surface = 2πrh + πr²

= πr(2h + r)

= `22/7 xx 10 xx (2 xx 7 + 10)`

= `220/7 xx 24`

= 754.29 cm²