Question

A current of 0.2 A flows through a conductor of resistance 4.5 Ω. Calculate the p.d. at the ends of the conductor.

Answer 1

I = 0.2 A; R = 4.5 Ω; V = ?

By Ohm's law, \[I = \frac{V}{R}\]

\[\therefore V = I.R\]

\[= 0.2 \times 4.5\]

= 0.9 V