हिंदी

A constantan wire has a length of 100 cm and a resistance of 12 Ω. If the specific resistance of constantan is 5 × 10^−3 ohm cm. Calculate the area of cross-section of wire.

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प्रश्न

A constantan wire has a length of 100 cm and a resistance of 12 Ω. If the specific resistance of constantan is 5 × 10−3 ohm cm. Calculate the area of cross-section of wire.

संख्यात्मक
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उत्तर

Given: l = 100 cm, R = 12 Ω, ρ = 5 × 10−3 Ω cm

Formula: \[R = \frac{\rho l}{A}\]

\[ A = \frac{\rho l}{R}\]

\[= \frac{(5 \times 10^{-3}\ \Omega \text{cm})(100\ \text{cm})}{12\ \Omega}\]

\[= \frac{0.5\ \Omega \text{cm}^2}{12\ \Omega}\]

= 0.041666 cm2

= 4.17 × 10−2 cm2

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अध्याय 7: Electric Circuits, Resistance and Ohm's Law - EXERCISE-1 [पृष्ठ १५०]

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गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics [English] Class 10
अध्याय 7 Electric Circuits, Resistance and Ohm's Law
EXERCISE-1 | Q 16. (b) | पृष्ठ १५०
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