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प्रश्न
A cone of height 30 cm is melted and recast into a cylinder of the same base. Find the height of the cylinder.
योग
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उत्तर
Given:
A right circular cone of height 30 cm is melted and recast into a cylinder having the same base (same radius r). This is a standard volume-conservation problem.
Let the common base radius = r and the required height of the cylinder = H cm.
Volume of cone = `(1/3)πr^2 × 30 = 10πr^2`.
Volume of cylinder = `πr^2 xx H.`
Equate volumes (material conserved): `πr^2 H = 10πr^2.`
Cancel `πr^2 (r ≠ 0): H`
= 10.
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