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प्रश्न
A concave lens has:
विकल्प
Positive power (\[f > 0\])
Positive power (\[f < 0\])
Negative power (\[f > 0\])
Negative power (\[f < 0\])
MCQ
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उत्तर
For a concave (diverging) lens the focal length is negative, \[f < 0\], and hence its power \[P = \frac{1}{f}\] is negative.
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