Question

A coin is tossed two times. Find the probability of getting at most one head.

Answer 1

The possible outcomes, if a coin is tossed 2 times is

S = {(HH), (TT), (HT), (TH)}

∴ n(S) = 4

Let E = Event of getting at most one head

= {(TT), (HT), (TH)}

∴ n(S) = 3

Hence, required probability = `(n(E))/(n(S)) = 3/4`