Question

A child has a die whose six faces shows the letters as given below:

\[\boxed{\text{A}}\]\[\boxed{\text{B}}\]\[\boxed{\text{C}}\]\[\boxed{\text{D}}\]\[\boxed{\text{E}}\]\[\boxed{\text{A}}\]

The die is thrown once. What is the probability of getting (i) A? (ii) D?

A child has a die whose six faces shows the letters as shown below:

\[\boxed{\text{A}}\]\[\boxed{\text{B}}\]\[\boxed{\text{C}}\]\[\boxed{\text{D}}\]\[\boxed{\text{E}}\]\[\boxed{\text{A}}\]

The die is thrown once. What is the probability of getting (i) A? (ii) D?

Answer 1

Total number of possible outcomes on the dice = 6

(i) Total number of faces having A on it = 2

`"Number of favourable outcomes"/"Total number of possible outcomes" = 2/6 = 1/3`

P (getting A) = `2/6 = 1/3`

(ii) Total number of faces having D on it = 1

Number of favourable outcomes = 1

`"Number of favourable outcomes"/"Total number of possible outcomes"= 1/6`

P (getting D) = `1/6`

Answer 2

Total possible outcomes, n(S) = 6

(i) Let E₁ = getting event letter A, then n(E₁) = 2

∴ Probability = `(n(E_1))/(n(S))`

= `2/6`

= `1/3`

(ii) Let E₂ = getting event letter D, then n(E₂) = 1

∴ Probability = `(n(E_2))/(n(S))`

= `1/6`