Question

1. Calculate the heat capacity of a copper vessel of mass 200 g if the specific heat capacity of copper is 410 J kg^-1 K^-1.
2. How much heat energy will be required to increase the temperature of the vessel in part (a) from 25°C to 35°C?

Answer 1

(a) Given,

mass (m) = 200 g = 0.20 kg

specific heat capacity (c) = 410 J kg^-1 K^-1

We know that,

Heat capacity (C^') = Mass (m) × specific heat capacity (c)

Substituting the values in the formula above we get,

C' = 0.20 × 410 = 82 J K^-1

Hence, heat capacity of a copper vessel = 82 J K^-1

(b) Change in temperature = 35°C - 25°C = 10°C = 10 K

Energy required to increase the temperature of vessel Q = ?

From relation,

Q = m × c × △T

Substituting the values in the formula above we get,

Q = 0.20 × 410 × 10 = 820 J

Hence, heat energy required to increase the temperature of the vessel = 820 J