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प्रश्न
A box contains nails of different lengths as shown below, the median class will be:
| Length (in cm) | 2.0 – 2.5 | 2.5 – 3.0 | 3.0 – 3.5 | 3.5 – 4.0 | 4.0 – 4.5 |
| No. of nails | 5 | 18 | 7 | 11 | 9 |
विकल्प
2.5 – 3.0
3.0 – 3.5
3.5 – 4.0
4.0 – 4.5
MCQ
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उत्तर
3.0 – 3.5
Explanation:
To determine the median class, we first need to construct a cumulative frequency table:
| Length (in cm) | No. of nails (f) | Cumulative Frequency (cf) |
| 2.0 – 2.5 | 5 | 5 |
| 2.5 – 3.0 | 18 | 5 + 18 = 23 |
| 3.0 – 3.5 | 7 | 23 + 7 = 30 |
| 3.5 – 4.0 | 11 | 30 + 11 = 41 |
| 4.0 – 4.5 | 9 | 41 + 9 = 50 |
1. Find the total frequency (N)
Total number of nails (N) = 5 + 18 + 7 + 11 + 9
= 50
2. Calculate
`N/2 = 50/2`
= 25
3. Identify the median class
Look for the first cumulative frequency that is greater than or equal to 25.
The cumulative frequency for the class interval 2.5 – 3.0 is 23 (which is less than 25).
The cumulative frequency for the next class interval 3.0 – 3.5 is 30 (which is greater than or equal to 25).
Thus, the median value lies within the interval 3.0 – 3.5.
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