Advertisements
Advertisements
प्रश्न
A body, when acted upon by a force of 10 kgf, moves to a distance 0.5 m in the direction of force. Find the work done by the force. Take 1 kgf = 10 N.
Advertisements
उत्तर
F= 10 kgf = 10 × 10N= 100 N,
Displacement S = 0.5 m
Work done
(i) When displacement is in the direction of force
W = F × S
W= 100 × 0.5 = 50 J
APPEARS IN
संबंधित प्रश्न
Write the formula for work done on a body when the body moves at an angle to the direction of force. Give the meaning of each symbol used.
Explain the difference between a uniform linear motion and a uniform circular motion.
How many joules are there in 1 mega joule?
Give two examples of work done.
Fill in the boxe to show the corresponding energy transformation.

State the energy changes which take place when A piece of magnesium wire is burnt in a jar of oxygen.
Define Translational motion.
A block of mass 30 kg is pulled up a slope, as shown in diagram with a constant speed, by applying a force of 200 N parallel to slope.
A and B are initial and final positions of block.

(i) Calculate the work done by force in moving the block from A to B.
(ii) Calculate P.E. gained by block. [g=10ms-2]
The work done by the heart is 1 Joule per beat. Calculate the power of the heart if it beats 72 times in one
