Question

A balloon vendor has 2 red, 3 blue and 4 green balloons. He wants to choose one of them at random to give it to Pranali. What is the probability of the event that Pranali gets, a green balloon.

Answer 1

Given:

Number of red balloons = 2

Number of blue balloons = 3

Number of green balloons = 4

Let S be the sample space.

∴ n(S) = Number of red balloons + Number of blue balloon + Number of green balloon

= 2 + 3 + 4

= 9

Let C be the event of getting a green balloon.

Given: n(C) = 4

∴ P(C) = `("n"("C"))/("n"("S"))`

= `4/9`

Hence, the probability that Pranali gets green balloon is `4/9`.

Answer 2

Let the 2 red balloons be R₁, R₂,

3 blue balloons be B₁, B₂, B₃ and

4 green balloons be G₁, G₂, G₃, G₄.

∴ Sample space,

S = {R₁, R₂, B₁, B₂, B₃, G₁, G₂, G₃, G₄}

∴ n(S) = 9

Let C be the event that Pranali gets a green balloon

∴ C = {G₁, G₂, G₃, G₄}

∴ n(C) = 4

∴ P(C) = `("n"("C"))/("n"("S"))`

= `4/9`

∴ The probability that Pranali gets a green balloon is `4/9`.