Question

A bag contains cards numbered from 1 to 25. A card is drawn at random from the bag. The probability that the number on this card is divisible by both 2 and 3 is

(A)`1/5`

(B)`3/25`

(C)`4/25`

(D)`2/25`

Answer 1

Total number of possible outcomes = 25
Let E be the event that the number on the card drawn is divisible by both 2 and 3.
∴  E = {6, 12, 18, 24}
∴ Number of outcomes favourable to E = 4

\[P(E) = \frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}} = \frac{4}{25}\]

Hence, the correct option is C.