Question

A bag contains 6 red, 8 black and 4 white balls. A ball is drawn at random. What is the probability that ball drawn is not black?

Answer 1

Total no. of possible outcomes = 18 {6 red, 8 black, 4 white}

Let E ⟶ event of drawing black ball.

No. of favourable outcomes = 8 {8 black balls}

Probability, P(E) =`"no.of favorable outcomes"/"Total no.of possible outcomes"` =8/18 =4/9

`barE`⟶ event of not drawing black ball

𝑃`(barE)` = 1 − 𝑃(𝐸)

= 1 − (4/9) =5/9