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प्रश्न
A(– 4, 2), B(6, 4) and C(2, – 2) are the vertices of $$\triangle \mathrm{ABC}$$. Find the co-ordinates of centroid of $$\triangle \mathrm{ABC}$$.
योग
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उत्तर
Centroid $$\mathrm{G}(x, y)$$ of $$\triangle \mathrm{ABC}$$:
$$x = \frac{-4 + 6 + 2}{3} = \frac{4}{3}$$
$$y = \frac{2 + 4 + (-2)}{3} = \frac{4}{3}$$
So, Centroid = $$\left(\frac{4}{3}, \frac{4}{3}\right)$$.
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अध्याय 14: Equation of a Straight Line - EXERCISE 14B [पृष्ठ २३२]
