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Π / 2 ∫ − π / 2 Log ( a − Sin θ a + Sin θ ) D θ

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प्रश्न

\[\int\limits_{- \pi/2}^{\pi/2} \log\left( \frac{a - \sin \theta}{a + \sin \theta} \right) d\theta\]
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उत्तर

\[Let\, I = \int_{- \frac{\pi}{2}}^\frac{\pi}{2} \log\left( \frac{a - \sin\theta}{a + \sin\theta} \right) d \theta\]

\[Here\, f\left( \theta \right) = \log\left( \frac{a - \sin\theta}{a + \sin\theta} \right)\]

\[Consider\, f\left( - \theta \right) = \log\left[ \frac{a - \sin\left( - \theta \right)}{a + \sin\left( - \theta \right)} \right] = - \log\left( \frac{a - \sin\theta}{a + \sin\theta} \right) = - f\left( \theta \right)\]

\[i . e . , f\left( \theta \right) \text{is odd function} . \]

\[\text{Therefore}, I = 0\]

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अध्याय 19: Definite Integrals - Very Short Answers [पृष्ठ ११५]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 19 Definite Integrals
Very Short Answers | Q 18 | पृष्ठ ११५

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